26 Anonymous In: Question-Answer What is the fewest number of consecutive primes, starting with 2, that when summed produce a number divisible by 7? 26 What is the fewest number of consecutive primes, starting with 2, that when summed produce a number divisible by 7? 1 Answer Voted Oldest Recent Random Best Answer Goto 2021-10-08T14:22:06+00:00Added an answer on October 8, 2021 at 2:22 pm The correct answer is: 5. The consecutive primes starting from 2 are 2, 3, 5, 7, 11 Summing gives 2 + 3 + 5 + 7 + 11 = 28 and 28 is divisible by 7 Thus the required number of primes is 5 9 Reply Share Share Share on Facebook Share on Twitter Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment.

The correct answer is: 5.

The consecutive primes starting from 2 are

2, 3, 5, 7, 11

Summing gives 2 + 3 + 5 + 7 + 11 = 28

and 28 is divisible by 7

Thus the required number of primes is 5